Question

Evaluate the indefinite integral of..
http://i1084.photobucket.com/albums/j409/QRAWarrior/MATA30/eu-Series1dx-IMG-003.png

e^u
----
(8 - e^u)^2

dx

Answer 1

I don't understand where I messed up here.

Answer 2

\[-\int u^{-2}du=u^{-1}+C\]is the only problem I see

Answer 3

yeah you kinda left the square off in the denominator
\[\int\limits_{}^{}-\frac{1}{m^2} dm=\int\limits_{}^{}-m^{-2} dm\]

Answer 4

\[\frac{-m^{-2+1}}{-2+1}+C\]