Question

A batter hits a baseball upward with an initial speed of 96 feet per second. After how many seconds does the ball hit the ground? Use the formula h = rt - 16t^2 where h represents height in feet and r represents the rate in feet per second.

Answer 1

We are assuming that he golfs the ball off of the ground and the initial height is 0?

Answer 2

h(t)=-16t^2+96t
-16t^2+96t=0
-16t(t-6)=0
t=0,6
6 seconds after he hits it, the ball hits the ground, assuming he golfed it off the ground which is unusual