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Find the volume of the solid by rotating the graph 9x^2+4y^2=36 about the y-axis
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always a good start to draw a picture with these to do that you need to recognize what kind of graph this is, and where the intercepts are
Yup. I did, and my intercepts were x=2 y=3
|dw:1330892545556:dw|because we're going around y, I think we should integrate along y and use disk method so we need an expression for the area of each disk, which means we need the radius
|dw:1330892756062:dw|the radius of each disk is\[r=f(y)=\frac23\sqrt{9-y^2}\]so the area of each disk is\[A(y)=\pi r^2=\frac{\pi}3(9-y^2)\]
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