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OpenStudy (anonymous):
For the system of linear equations below, use graphing to determine in which quadrant the solution lies. x+2y=-2 -2x+y=14
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OpenStudy (anonymous):
Well you have to put the two equations in y=mx + b form.
OpenStudy (anonymous):
Huh?
OpenStudy (anonymous):
x+2y=-2 -x -x 2y = -x - 2 /2 /2 /2 y = (-x/2) - 1
OpenStudy (anonymous):
So would that be in quadrant IV?
OpenStudy (anonymous):
Let me see
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OpenStudy (anonymous):
No the solution would be in quadrant II
OpenStudy (anonymous):
Okay thanks :-)
OpenStudy (anonymous):
No prob :)
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