Question

How can I solve this proble. -3(x-20≤3-2X≤10-3X

Answer 1

Gilbertv, you missed the closed parantheses
-3x-20 ≤ 3-2X ≤ 10-3X

Answer 2

fix your question, will you?

Answer 3

Here is the problem \[-3\left( x-2 \right)\le3-2x \le10-3x\]

Answer 4

−3(x−2) ≤ 3−2x
-3x + 6 ≤ 3−2x
-> 6 -3 ≤ −2x + 3x
=> x >= 3

3−2x ≤ 10−3x
3x -2x ≤ 10 - 3
->x ≤ 7
Thus 3 ≤ x ≤ 7 or x belongs to closed interval [ 3, 7 ]

Answer 5

Thank you