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OpenStudy (anonymous):

Grade 9 Pascal Contest 2012 #24 The smallest of 9 consecutive integers is 2012. These nine integers are placed in the circles shown in the diagram. the sum of the three integers along each of the four lines is the same. If the sum is as small as possible, what is the value of u?

OpenStudy (anonymous):

|dw:1330047456318:dw|

OpenStudy (akshay_budhkar):

u gave the exam today?

OpenStudy (anonymous):

yeah, but i didn't get this one

OpenStudy (akshay_budhkar):

ok lets do it together.. the paper was easier than last year though.. Ok you have the 9 consecutive integers .. um doesnt hit and trial help?

OpenStudy (anonymous):

ya, here are the options a) 2012 b) 2013 c) 2014 d) 2015 e) 2016

OpenStudy (anonymous):

the 9 numbers would be 2012, 2013, 2014, 2015, 2016, 2017, 2018,2019, 2020 but it would take forever to try every number since the sum of the numbers in each "line" must be the same

OpenStudy (anonymous):

A

OpenStudy (anonymous):

how did you get a) 2012 as the answer?

OpenStudy (anonymous):

|dw:1330240890366:dw|

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