Question

I'm trying to figure out why this area = 1/2*AB*BD*sin(theta)

Is it because if we draw the altitude DE, then sin(theta) is DE/BD, the two BDs in the original equation cancel and we're left with altitude (height) DE? Or am I off track?

Answer 1

Is this the given triangle?

Answer 2

yes it is

Answer 3

Let me draw it better so you understand.....