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Rewrite with positive exponents. Assume that even roots are of nonnegative quantities and that all denominators are nonzero. (3y(2/3))^-3
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(3^(-3)y^(-2)) = 1/(27y^2)
this is what i got so tell me did i do it wrong
3^(-3) y^(-3 * 2/3) = 3^(-3) y^(-2) = .1 . . .1 . . . . . . . 1 ---- x ---- . = . ---------- 3^3 . y^2 . . . . 3(3y)^2
that's correct btw
ok thank u so much
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