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OpenStudy (anonymous):
Jim has 6.75 in dimes and quarters he had 8 more dimes than quarters how many coins of each type
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hero (hero):
.25x + .10y = 6.75
y = x + 8
hero (hero):
y = (6.75 - .25x)/.10
y = x + 8
y = y
.10(x+8) = 6.75 - .25x
.10x + .8 = 6.75 - .25x
.35x = 5.95
x = 5.95/.35
x = 17
y = 25
17(.25) + 25(.10) = 6.75
hero (hero):
Good luck figuring that out
OpenStudy (anonymous):
what do you mean?
hero (hero):
I'm sure you will have no problem understanding my steps.
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OpenStudy (anonymous):
I am working on it.
hero (hero):
Okay
OpenStudy (anonymous):
If there is something helpful you can clue me in on please do
hero (hero):
It's pretty straight-forward from my point of view. Is there a step you're stuck on?
OpenStudy (anonymous):
I will have to continue to look at it. thanks
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hero (hero):
Hint: at one point while solving, you cross-multiply. Good luck.
OpenStudy (anonymous):
sounds more like a riddle than trying to help me understand. I will have my tutor help me on this one, but thanks for your effort.
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