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the inverse of 3x+4/2x-3
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solve \[x=\frac{3y+4}{2y-3}\] for y you need the steps?
no
ok
i did it, but i'm not sure of it
:D
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i think this function is its own inverse
oh
i can write out the steps if you like
okay
\[x=\frac{3y+4}{2y-3}\] \[x(2y-3)=3y+4\] \[2xy-3x=3y+4\] \[2xy-3y=3x+4\] \[y(2x-3)=3x+4\] \[y=\frac{3x+4}{2x-3}\] same thing
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yeah :d thks alot
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