Question

how do you solve x^2-x+56=17x

Answer 1

\[x^2-x+56=17x\]
\[x^2-18x+56=0\]
\[a=1, b=-18, c=56\]
\[x=(18\pm \sqrt{(-18)^{2}-4(1)(56)})/(2(1))\]
x=4 and x=14 are the solutions


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