In a quadrilateral MNOP the length of side MN is (4x - 7) units and the length of side ON is (7 – 3x) units. What value of x will make it a rhombus?2
7
12
14

Question

In a quadrilateral MNOP the length of side MN is (4x - 7) units and the length of side ON is (7 – 3x) units. What value of x will make it a rhombus?2
		7
		12
		14

aroub · Answer

If you want to make a quadrilateral a rhombus then the sides must be congruent!

So, MN=ON

and they gave you the length of each sides:

MN= 4x-7 
ON=7-3x

Just substitute and solve:

MN=ON
4x-7=7-3x
4x+3x=7+7
7x=14
x=2

anonymous · Answer

Yeah i finally understand. Thanks! Also what i did was i plugged in the answer from below and 2 made both sides equal 1.

aroub · Answer

Yes! That's a nice way. If you were in a hurry ( in the exam ) you could just substitute the choices you have in the 'sides' and if you got 2 congruent sides then that's the answer :)