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Find the tangent line to 4x^2-3y^2=13 at the point (-2,1). Express your answer in the form y=mx+b.
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Take the derivative, then substitute the point
first differentiate the function this will give u slope of the tangent then use general form of straight line substituting the given point
how can i differetitate i know how to take the derivate of 4x^2-3y^2 but i dont know how to solve it when it equals 13
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