Question

I want to convert a char to int like '7' to 7 (in C++) but every time I try it gives me its ASCII value. Basically I just want to multiply two characters like '7' * '7' = 49.

Answer 1

I solved a similar problem to this in Java by subtracting the appropriate amount from the ascii value. So numerals 0-9 ascii values are 30-39, so simply subtract 30 from your ascii value and assign it to the variable that you want.

Pseudo code:
Print "Enter a number: "
Input numString
Parse numString to numAscii
numInt=numAscii-30
numInt=numInt*7
Print numInt

Answer 2

You could also mod 10 the ascii value.

Answer 3

for the '0' to '9' ASCII characters, just subtract '0' (the character) from it, because character literals in C (and i think C++ as well) are just integer values of their ASCII encoding.

for example: http://ideone.com/noXGk

Answer 4

Thanks agdg. I knew you'd pipe in with something useful.