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Mathematics 10 Online
OpenStudy (anonymous):

k^(2)+13k

OpenStudy (anonymous):

k=0 , k= -13

jhonyy9 (jhonyy9):

k(k+13)=0 k=0 k+13=0 k=-13

Directrix (directrix):

k^(2)+13k = k(k + 13) No instructions are given so I assume that the task is to factor the expression. Others have transformed the expression into an equation and found its zeros.

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