Ask your own question, for FREE!
Mathematics 28 Online
OpenStudy (anonymous):

Solve p-3√(p) =10

OpenStudy (anonymous):

p-10=3*sqr(p)

OpenStudy (anonymous):

now jst squaring both sides

OpenStudy (anonymous):

u get quadratic in "p"

OpenStudy (anonymous):

\[3\sqrt{p}=p-10\] \[3\sqrt{p}=p-10\] squre both sides \[9p=p^2-20p+100\] \[p^2-29p+100=0\] \[(p-25)(p-4)=0\] \[p=25,4\] p=4 4-6=10? false, discard p=4 p=25 25-15=10? true, p=25 is the solution

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!