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3^(4x-7)=4^(2x+3) solve for x and show me the steps please!
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x = (-6 log2-7 log3) / (4 (log2-log3))
or about 7.31
The first step is to take log of each side: (4x-7) log 3 = (2x+3) log 4 Then solve for x the usual way.
If you need it, the next step would be 4log3 x - 7log3 = 2log4 x + 3log4
thx!!!!!!!
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