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Find the perimeter of a triangle with vertices (2,4) (-1,3) and (2,-3).
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(2,4) (-1,3) ---> √10 (-1,3) and (2,-3). ---> √45 (2,4) and (2,-3) ----> 7 perimeter = 7 + √45 +√10 = 7 + √10 + 3√5 ---> That's it --> these are not like terms. You can approximate the value of the radicals. but I don't know the instructions you had regarding that. Note: √45 = √(3*3*5) = 3√5
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