OpenStudy (anonymous):
Geometry Help, Please "find the lateral area of the pyramid to the nearest whole number" #4 Picture attached
OpenStudy (anonymous):
#4
Directrix (directrix):
|dw:1330116623674:dw| LA = (1/2) perimeter of base times the slant height perimeter of square base = 4(12) = 48 The slant height is the altitude of one of the congruent triangular faces. It has length 6 √2. The diagram shows an "x-ray" inside the regular pyramid with a right triangle shown. One leg of the triangle is 6, the altitude of the pyramid. The other leg is 1/2 a base edge and is 6. The right triangle formed is an isosceles right triangle. The hypotenuse is √2 times its leg or 6 √2. You can also use the Pythagorean Theorem. LA = (1/2) perimeter of base times the slant height LA = (1/2)* 48* 6 √2 LA = 144 √2 square meters or 204 square meters to the nearest whole square meter
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