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OpenStudy (anonymous):
lim [x2 + 11x + 10] / [x^2+x] x->-1
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OpenStudy (anonymous):
lim (x+10)(x+1)/[x(x+1)]= x->-1 lim->-1 (x+10)/x
OpenStudy (anonymous):
=-9
OpenStudy (anonymous):
How about ? lim [x^3 + 8]/ [x^2 + 7x + 10] x->-2
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