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Mathematics 63 Online
OpenStudy (anonymous):

lim [x2 + 11x + 10] / [x^2+x] x->-1

OpenStudy (anonymous):

lim (x+10)(x+1)/[x(x+1)]= x->-1 lim->-1 (x+10)/x

OpenStudy (anonymous):

=-9

OpenStudy (anonymous):

How about ? lim [x^3 + 8]/ [x^2 + 7x + 10] x->-2

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