A rectangular box for a new product is designed in such a way that the three dimensions a particular relationship defined by the variable x. The volume of the box can be written as:
6x^3 + 31x^2 + 53x + 30
and the height is always x+2. What are the width and height of the box?
PLEASE NO ANSWERS just explain how I would get there. I assume it has something to do with synthetic division since that is what this section is on.

Question

A rectangular box for a new product is designed in such a way that the three dimensions a particular relationship defined by the variable x. The volume of the box can be written as:
6x^3 + 31x^2 + 53x + 30
and the height is always x+2. What are the width and height of the box?
PLEASE NO ANSWERS just explain how I would get there. I assume it has something to do with synthetic division since that is what this section is on.

accessdenied · Answer

Yes, you could use synthetic division to get a quadratic.

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