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sinx/cosx=tanx, its a trig identity
We have \[ \mu W \cos \theta= W \sin \theta \] Divide both sides by W we get \[ \mu \cos \theta=\sin \theta\] Divide both sides by cos theta \[\mu=\frac{\sin \theta}{\cos \theta}\] We get \[\mu =\tan \theta\]
yay thanks i got the same answer :D i was checking
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