Question

Find the perimeter of a triangle with vertices (2,4) (-1,3) and (2,-3)

Answer 1

\[ D_{distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]
Use this for all three sides and add together for perimeter

Answer 2

thank you

Answer 3

no i think i messed it up again

Answer 4

i didnt get sqrt(58) --
-3 - 3 = -6
2 - -1 = 2 + 1 = 3

(-6)^2 + 3^2 = 36 + 9 = 45

Answer 5

i got sqrt(10) and 7, but sqrt(45) = 3sqrt(5) for second and third point's distance