Question

PLEASE HELP SEE ATTACHMENT

Answer 1

We have
\[7x^2+3y^2=187\]
\[3y^2-7x=47\]
Let's subtract 2nd from 1st, we get
\[7x^2+3y^2-(3y^2-7x)=187-47\]
we get
\[7x^2+7x=140\]
divide the whole equation by 7
\[x^2+x=20\]
subtract both sides by 20
\[x^2+x-20=0\]
rini do you know how to solve a quadratic equation? Do you know what is the sum of roots of a quadratic?

Answer 2

yes

Answer 3

Solve it and tell what are the roots?

Answer 4

-5,4

Answer 5

great , the sum of these is your answer

Answer 6

-1

Answer 7

thank you!

Answer 8

welcome :D