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I am to a certian point and I need to know if I simplify further 3(x+2)(x-9)=(x+7)/3
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or better yet how do I solve the equation when I get to (x+7)/3
The original equation was this; log3(x+7)-1=log3(x+2)-log3(x-9)
log3 [ (x + 7)/ 3 ] = log3 [(x+2)/ (x +9)] -> (x + 7)/ 3 = (x+2)/ (x +9) -> (x + 7) (x +9) = 3(x+2) -> x^2 -16x + 63 = 3x + 6 => x^2 - 19x + 57 = 0
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