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Mathematics 13 Online
OpenStudy (anonymous):

(12x^2-4x-8)/4x

OpenStudy (anonymous):

that's better and clear now we divide each term by the denominator and get (3x - 1) - 2/x or we can put answer as (3x^2 - x - 2)/x

sam (.sam.):

(12x^(2)-4x-8)/(4x) (4(3x^(2))+4(-x)+4(-2))/(4x) (4(3x^(2)-x-2))/(4x) (4(x+(2)/(3))(x-1))/(4x) 4(3x+2)(x-1)/(4x) (3x+2)(x-1)/(x)

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