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Linear Algebra: Show that if A is skew-symmetric, then A is a square matrix which has only zeros on its main diagonal.
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A is skew-symmetric then its transpose= -A a(ij) = - a(ji) the limits of i and j must be the same => A has same number of columns and rows => it is a square matrix for the diagonal a(ii) = -a(ii) which is only true for a(ii)=0
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