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Just another cute problem, How many eight digit numbers formed using the digit \( \{7,8,9\} \) has exactly three \( 7 \)'s ?
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If I get the question right then the answer should be \(8\cdot 7\cdot 6\cdot {5\choose 2}\).
@Mr.Math: http://openstudy.com/users/foolformath#/updates/4f4a52fee4b00c3c5d335536
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