Question

(cos(180−x)sin(x−90)−1)\[÷
tan^2(180+x)\sin(90+x)\cos(-x)\]

Answer 1

cot^2(180+x) csc(90+x) sec(x) (-1-cos(180-x) sin(90-x))

Answer 2

thanks for the help but cot and sec is not in our syllabus , we dont learn it in school

Answer 3

oh i see but just to let u know the cot is actually the inverse of tangent and sec is the inverse of cosine......inverse or reciprocal same meaning......so dun worry u just make them 1/(answer of cot) and do that for sec ....ok

Answer 4

okay cool thanks sooo much , i really appreciate it :)

Answer 5

oh sure no worries :) glad to help only if i know the right answer haha...kk