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The perimeter of a regular hexagon is 108. What is its area?
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108/6=18, length of hexagon edge A=(3*sqrt(3)/2)*t^2, where t is the edge length A=841.7767
omar_86 i cannot fnd that answer in my list.
what options u have?
30, 41,31,0
and the perimeter is 108?
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sorry i gave the choices to the wrong question.
486*square root 3, 81*square root 3, 729, 729*square root 3
it's 486*square root 3
can you please explain for clarification thanks.
the law of hexagon area is: 3*sqrt(3) -------- * t^2 2 where t is the edge length, ok till now?
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thank u im fine
we divide the whole perimeter length by 6, since hexagon, to get the edge length, in this case 108/6=18
then substitute 18 into the previous equation instead of t
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