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HELP: how do you find the smallest number divisible by both 715 and 770?
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Divide by 5?
yeah its 5
the answer is 10010
its the LCM you're looking for 770=2x5x7x11 715=5x11x13 so LCM(770;715)=2x5x7x11x13=10010
how do you go about finding the LCM?
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factor each number 715 = 5 * 11 * 13 as ghass says
first do the prime factorization of each number the LCM is the product of all factors raised to the highest power
how do you know which are raised to the highest power ?
well in our case all the powers are 1 but for example if a=2^2x3^4 and b=2x3^2x7 then LCM(a,b)=2^2x3^4x7=...
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