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im in community college math 107 the question asks determine which values could be used to clear the frections in the given equation. select all that apply. 1/3(x) - 5/6 = x/9 a. 6 b. 9 c. 12 d. 18 e. 33 f. 36 right off the practice quiz
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18 and 36
yea but howd you get that...
figure out which numbers 3,6 and 9 go into without any remainders.
ohhh i seee now thank you
no prob :)
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okay so i distributed 18/1(1/3x-5/6) = x/9(18/1) and got 6x-15=2x -15= -4x 3.75=x.... i dont get how thats what x is...
is the question just asking to find what numbers the denominators can go into?
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