Solve for x in the proportion 9 over 27 times x equals x over the quantity x plus 3.
Answer

x ˜ -0.85 and x ˜ 1.18

x ˜ -6 and x ˜ 6.16

x ˜ -2.48 and x ˜ 2.48

x = 2 and x = 0

Question

Solve for x in the proportion 9 over 27 times x equals x over the quantity x plus 3.
Answer
		
x ˜ -0.85 and x ˜ 1.18
		
x ˜ -6 and x ˜ 6.16
		
x ˜ -2.48 and x ˜ 2.48
		
x = 2 and x = 0

anonymous · Answer

9/27x = x/(x+3)

9(x+3) = 27x^2

0 = 27x^2 -9x - 27

0 = x^2 - (1/3)x - 1

1 = (x - 1/6)^2 - 1/36

37/36 = (x - 1/6)^2

sqrt(37/36) plus/minus 1/6 = x

anonymous · Answer

sorry plus minus sqrt(37/36) + 1/6 = x

so x = -.85 or 1.18

radar · Answer

(9/27x)=x/(x+3)
27^2-9x-27=0     divide by 9
3x^2-x-3=0
Using quadratic equation:
$$1\pm \sqrt{1 + 36}\over6$$
First one is the solution