Question

the function f is given by the formula ƒ(x)= 6x^3-11x^2+7x-18÷ x-2 when x<2 and by the formula ƒ(x)=2x^2-5x+a when 2≤x What value must be chosen for a in order to make this function continuous at 2?

Answer 1

The two functions must have the same value at x=2
This won't gaurantee continuity, but it's necessary.

Answer 2

I think 37. I divided the first function and set the quotient equal to the second function, replaced x with 2 and solved for a.