Question

8x+x(x-2)=0
(0,-6)?

Answer 1

Zero in and zero out.

8x+x(x-2)=0

8*0 + 0*(0 - 2) = 0 ---> (0,0)

Answer 2

8x + x(x - 2) = 0
8x + x^2 - 2x = 0
x^2 + 6x = 0
(x + 3)^2 - 9 = 0
(x + 3)^2 = 9
x + 3 = plus/minus 3
x = -3 plus/minus 3
so x = 0, -6

Answer 3

ok now i have to figure out the x-intercepts

Answer 4

those are the x intercepts, 0 and -6

Answer 5

ok i solved for the solution and got that answer, so its the same anwer for the x intercepts??

Answer 6

yes, if y = 8x+x(x-2) then y would be 0 at x = 0, -6
so the parabola crosses the x axis at 0, -6