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Find the perimeter of a triangle with the vertices (2,4) (-1,3) and (2,-3)
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You should really just graph it. Are you allowed to?
yea
Then I guess just do that.
ok thanks
If you get any problems with diagonals, remember, slope= y2-y1/x2-x1. Ok?
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Or, subtract the "1st point" from the "2nd point".
(2,4) (-1,3) and (2,-3) -2-4 -2-4 -2-4 ----------------- 0,0 -3,1 0,-7 sqrt(10) 7 (2,4) (-1,3) and (2,-3) 1-3 1-3 1-3 -------------------- 3,1 0,0 3,0 sqrt(10) 3 7+3+sqrt(10) = 10+sqrt(10)
you dont need slope; you need distance
oops
its still subtract tho ;)
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