Question

Evaluate the Indefinite Integral of sqrt(16x-x^2) dx

Answer 1

Complete the square of the integrand to get 64-(x-8)^2

Answer 2

Then let u = x-8 and du = dx

Answer 3

Now you have;
\[\int\limits_{?}^{?}\sqrt{64-u^2}du\]

Answer 4

Substitute u = 8sin(s) and du = 8 cos(s)ds