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OpenStudy (anonymous):
How to factor: x^2+2x+3x+6 Steps please :) Thanks!
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OpenStudy (anonymous):
\[x^2+2x+3x+6\]
OpenStudy (mertsj):
(x+3)(x+2)
OpenStudy (anonymous):
(x-2)(x+4)
OpenStudy (anonymous):
Can you show me how you guys got that?
OpenStudy (anonymous):
yep
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OpenStudy (mertsj):
\[x^2+2x+3x+6=x^2+5x+6=(x+3)(x+2)\]
OpenStudy (anonymous):
yep. what she said
OpenStudy (mertsj):
Or you could do it this way:
OpenStudy (mertsj):
\[x(x+2)+3(x+2)=(x+2)(x+3)\]
OpenStudy (mertsj):
That would be called factor by grouping.
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OpenStudy (anonymous):
yaaa!
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