Question

Nerd is in need,again!!! ima cry if no one replies
find all solutions of the equation in the interval [0,2pi) sin(x+3pi/2)-sin(x-3pi/2)=0

Answer 1

use sum and difference formulas
sin(x+y) = sinxcosy + sinycosx
sin(x-y) = sinxcosy - sinycosx

Answer 2

okay so how would i go about this?

Answer 3

well, in this case y=3pi/2
sin 3pi/2 = -1
cos 3pi/2 = 0

Answer 4

equation reduces to
-cos x -cos x = 0
-2cos x = 0
cos x = 0

x = pi/2, 3pi/2

Answer 5

thank u dumbcow! :]