Question

Part 1:
Solve the following system of equations. Please show your work to receive full credit.
x - y = 10
2x + y = 2

Part 2:
Explain which method you chose to solve the system and why you felt it was the best choice.

Explain to me plz!

Answer 1

add both the equations
to get
3x = 12
x=4 and y = -6

Answer 2

x-y=10------(1)
2x+y=2------(2)
from (1),x=10+y.
So,from (2), 2x+y=2
2(10+y)+y=2
20+3y=2
3y=-18
y=-6

Answer 3

We have
\[x-y=10\]
and
\[2x+y=2\]
Let's add both the equations, this will eliminate y
\[x-y+2x+y=12\]
\[x-\cancel y+2x+\cancel y=12\]
\[3x=12\]
divide both sides by 3
we get
\[x=4\]
Now use first equation \(x-y=10\) , let's substitute x=4 here
\[4-y=10\]
subtract both sides by 4 , we get
\[-y=6\]
we get
\[y=-6\]
Here we have used elimination method because it was easy to apply here. We just added the two equations to eliminate y and were able to find x.