Consider the substitution reaction of H2S-BH3 with NH3, which generates two molecules (ignore the states of matter), assuming that no species exceeds the octet rule. Given the following information:
Step 1: There are two products in the first step; one product, which is an intermediate, has a trigonal planar molecular geometry.
Step 2: The intermediate from Step 1 reacts in Step 2 to form a compound with two sp^3 hybridized atoms.
Overall: One bond is formed and one bond is broken. One of the products has a bent molecular geometry and smells like rotten eggs.

Question

Consider the substitution reaction of H2S-BH3 with NH3, which generates two molecules (ignore the states of matter), assuming that no species exceeds the octet rule. Given the following information:
Step 1: There are two products in the first step; one product, which is an intermediate, has a trigonal planar molecular geometry.
Step 2: The intermediate from Step 1 reacts in Step 2 to form a compound with two sp^3 hybridized atoms.
Overall: One bond is formed and one bond is broken. One of the products has a bent molecular geometry and smells like rotten eggs.

anonymous · Answer

a) Propose a mechanism for this reaction.
b) Draw the Lewis structures of both products, including all lone pairs and formal charges.