Question

\[\sqrt{8}-\sqrt{2}\]

how do you get sqrt 2 as your answer

Answer 1

\[\sqrt{8}-\sqrt{2}\]
\[2\sqrt{2}-\sqrt{2}\]
\[(\sqrt{2}*\sqrt{2})-\sqrt{2}\]
\[(\sqrt{2}*\cancel{\sqrt{2}})-\cancel{\sqrt{2}}\]
\[\sqrt{2}\]

Answer 2

\[\sqrt{8}= \sqrt{4\times2}=2\sqrt{2}\]

\[2\sqrt{2}-\sqrt{2}= \sqrt{2}\]

Answer 3

After you guys are done with this question, can someone help me with mine?

Answer 4

solution given by agreene is incorrect