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x^2+3x-5=0
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complete the square or use the quadratic formula to get \[x=(-3\pm \sqrt{29})/2\]
\[x ^{2}+3x-5=0 \rightarrow x ^{2}+3x=5 \rightarrow x ^{2}+3x+(9/4)=5+(9/4)\rightarrow(x+3/2)^{2}=29/4\\[\rightarrow x+3/2=\pm \sqrt{29}/2 \rightarrow x=(-3\pm \sqrt{29})/2\]]
Apparently haven't mastered the equation editor yet, but I outlined how to complete the square above.
-3/2 - sqrt29/2 and sqrt29/2 - 3/2
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