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Mathematics 16 Online
OpenStudy (anonymous):

question attached

OpenStudy (anonymous):

OpenStudy (anonymous):

The derivative of y^2 with respect to y is...2yy'!

sam (.sam.):

dy/dx= 8x/2y

OpenStudy (anonymous):

should be \[8x-2yy'=0\] by the chain rule

OpenStudy (anonymous):

Woops, I mean with respect to x.

OpenStudy (anonymous):

solve for \[y'\]get \[y'=\frac{4x}{y}\]

OpenStudy (anonymous):

THANK YOU :D

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