Question

if f(x)= tan5x- sin2x, find f(pi/6)

Answer 1

\[\tan \frac{5\pi}{6}-\sin \frac{\pi}{3}=\frac{-\sqrt{3}}{3}-\frac{\sqrt{3}}{2}=\frac{-2\sqrt{3}-3\sqrt{3}}{6}=\frac{-5\sqrt{3}}{6}\]

Answer 2

thank you. :)

Answer 3

yw