Question

Solve 2n^2-7n-3=0 using quadratic formula?

Answer 1

write in term of \[aX ^{2}+b(X)+c=0\] where a=2, b=-7 and c=-3
then pluggin those a,b,and c into this equation
\[[(-b)\pm \sqrt(b ^{2}-4ac)]\div(2a)\]