Question

Let f(x) =25/x
The slope of the tangent line to the graph of f(x) at the point (-6,-25/6) is __________????
The equation of the tangent line to the graph of f(x) at (-6,-25/6) is y=mx+b for m=__________????

Answer 1

Differentiate f(x) and you will get f'(x)=-25/x^2
key in x=-6 into f'(x) and you will get the slope.

b) use (y-y1)=m(x-x1) form your point that u have there.

Answer 2

@bboy, follow yernpaul solution. .

Answer 3

thanks guys, I'm trying that now