Question

I am really confused. Solve the following system of linear equations by substitution:
-2x+6y=24
3x-2y=-1

Answer 1

Divide 1st equation by -2.
x-3y=-12
x=3y-12 substitute it into the 2nd eq-n
3(3y-12)-2y=-1
9y-36-2y=-1
7y-36=-1
7y=-1+36=35
y=5

Answer 2

-2x+6y=24
3x-2y=-1
-------------------
y=(24+2x)/6
3x-2(24+2x/6)=-1
--------------------
x=3
y=5

Answer 3

use y value in 1st eq-n
x-3*5=-12
x-15=-12
x=-12+15=3
(3,5)