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MnO2+4HCl2->MnCl2+2H2O

a.) If 0.86 mole of MnO2 and 48.2 g of HCl react , wgat is thr limiting reagent?
b.) How many grams of Cl2 will be produced ?

Answer 1

1. MnO2 since because of the ratios the .86 will run out first
2. i don't have a calculator but .86 mol of MnCl2 will form because it's a 1:1 ratio and divide out the weight ratio of Mn to Cl2 to find out how much Cl2 is produced

Answer 2

what must i do first?:)