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A group of people spent exactly $100 on tickets to a show. Adult tickets cost $11 and child tickets cost $8. How many children were in the group?
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A*8 + B*11 = 100
11x4=44 7x8=56 56+44=100
7 kids 4 adults
yeap 7kids n 4 adults
Romero wrote an equation A*8+B*11 = 100. If were not given how many tickets are sold then we can do a guess and check method. If you plug in values for B you will find that when B = 4, then B*11 = $44. So if we take the original $100 and subtract $44 we get 56, which is divisible by 8.
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thanx you guys
Where A and B have to be positive integers. The only solution for which satisfies the equation is 7 kids and 4 adults
thanx
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